12-8[3x-5x(2-x)]=8x(7-5x)

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Solution for 12-8[3x-5x(2-x)]=8x(7-5x) equation: 


Simplifying
12 + -8[3x + -5x(2 + -1x)] = 8x(7 + -5x)
12 + -8[3x + (2 * -5x + -1x * -5x)] = 8x(7 + -5x)
12 + -8[3x + (-10x + 5x2)] = 8x(7 + -5x)

Combine like terms: 3x + -10x = -7x
12 + -8[-7x + 5x2] = 8x(7 + -5x)
12 + [-7x * -8 + 5x2 * -8] = 8x(7 + -5x)
12 + [56x + -40x2] = 8x(7 + -5x)
12 + 56x + -40x2 = (7 * 8x + -5x * 8x)
12 + 56x + -40x2 = (56x + -40x2)

Add '-56x' to each side of the equation.
12 + 56x + -56x + -40x2 = 56x + -56x + -40x2

Combine like terms: 56x + -56x = 0
12 + 0 + -40x2 = 56x + -56x + -40x2
12 + -40x2 = 56x + -56x + -40x2

Combine like terms: 56x + -56x = 0
12 + -40x2 = 0 + -40x2
12 + -40x2 = -40x2

Add '40x2' to each side of the equation.
12 + -40x2 + 40x2 = -40x2 + 40x2

Combine like terms: -40x2 + 40x2 = 0
12 + 0 = -40x2 + 40x2
12 = -40x2 + 40x2

Combine like terms: -40x2 + 40x2 = 0
12 = 0

Solving
12 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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